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A golf ball is hit so that it leaves the club face at a velocity of 45 m/s at an angle of 60° to the horizontal. Calculate The horizontal component of the velocity.

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Final answer:

The horizontal component of the velocity can be calculated using the equation Vx = V * cos(θ), where V is the initial velocity and θ is the angle of launch.

Step-by-step explanation:

When a golf ball is hit, it has both a horizontal and a vertical component to its velocity. In this case, the golf ball is hit at an angle of 60° to the horizontal and has a velocity of 45 m/s. To find the horizontal component of the velocity, we can use trigonometry. The horizontal component can be found using the equation Vx = V * cos(θ), where Vx is the horizontal component of velocity, V is the initial velocity, and θ is the angle of launch. Plugging in the given values, we get:



Vx = 45 m/s * cos(60°)



Vx = 45 m/s * 0.5



Vx = 22.5 m/s

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