Question

A lead rod has a length of 133.4 m when the temperature is 22.8 degrees celsius. What is its length when the temperature is 59.8 degrees celsius?

Note: Your answer must be in meters, however, do not include the unit, just enter the magnitude that correspond to the final length in meters. Round your answer to 2 decimal points. the coefiicient for linear expansion for lead = 29*10^-6

Answer 1

The change in length of the lead rod when the temperature increases by 37°C is 0.15m.

Step-by-step explanation:

To calculate the change in length of the lead rod, we can use the equation for linear thermal expansion: ΔL = α * L * ΔT, where ΔL is the change in length, α is the coefficient of linear expansion, L is the initial length, and ΔT is the change in temperature.

Given that the coefficient of linear expansion for lead is 29 * 10^-6, the initial length is 133.4m, and the change in temperature is 59.8°C - 22.8°C = 37°C, we can substitute these values into the equation to find the change in length:

ΔL = (29 * 10^-6) * (133.4m) * (37°C) = 0.14696m = 0.15m (rounded to 2 decimal places).