Question

In the figure the Red charge is +3.0 nC and located 4.0m from the origin on the y-axis, coordinate (0,4). The Blue charge is -12.0 nC and located 3m from the origin on the x-axis, coordinate (3,0). The Green charge is +10 nC and located at the origin, coordinate (0,0). The electric potential at point P(3,4) due to the Red charge is:

Answer 1

The electric potential at point P due to the Red charge is calculated using the formula V = kQ/r, which results in an electric potential of 8.99 volts.

Step-by-step explanation:

To calculate the electric potential at point P(3,4) due to the Red charge, we will use the formula for the electric potential V due to a point charge, which is V = kQ/r, where k is Coulomb's constant (k = 8.99 x 109 N*m2/C2), Q is the charge, and r is the distance from the charge to the point at which the potential is being calculated.

To begin with, we must find the distance r between the Red charge and point P. Since the Red charge is at (0,4) and point P is at (3,4), we can use the Pythagorean theorem to calculate the distance:

r = √((3-0)2 + (4-4)2) = √(32) = 3 m

Now, we can plug the values into the electric potential formula:

V = (8.99 x 109 N*m2/C2) * (+3.0 x 10-9C) / 3 m

V = (8.99 x 109 * 3.0 x 10-9) / 3

V = 8.99 volts

Therefore, the electric potential at point P due to the Red charge is 8.99 volts.