Question

How many zinc atoms are contained in 7.66x10⁵ mmol of zinc?

4.61 10²⁶Zn atoms
3.24 10²⁶ Zn atoms
1.15 10²⁸ Zn atoms
4.6110²⁹ Zn atoms
786 10²¹ Zn atoms

Answer 1

There are 4.61 x 10²¶ zinc atoms in 7.66 x 10⁵ mmol of zinc. This is calculated by converting millimoles to moles and then using Avogadro's number to find the total number of atoms.

Step-by-step explanation:

To calculate how many zinc atoms are contained in 7.66 x 10⁵ mmol of zinc, we use Avogadro's number which states that one mole of any substance contains 6.022 x 10²³ atoms. First, we convert millimoles to moles by dividing by 1000.

7.66 x 10⁵ mmol x (1 mol / 1000 mmol) = 7.66 x 10² mol

Now, we can find the number of atoms by multiplying the number of moles by Avogadro's number.

7.66 x 10² mol x (6.022 x 10²³ atoms/mol) = 4.61 x 10²¶ Zn atoms

The correct answer is that there are 4.61 x 10²¶ zinc atoms in 7.66 x 10⁵ mmol of zinc.