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Let of be the function given by f(x) = (cosx)e²ˣ-1/e²ᵉ-ˣ-1+2 What are all horizontal asymptotes to the graph of f?

(A) y = -½ only
(B) y = e only
(C) y = - and y = e
(D) The graph of f has no horizontal asymptotes.

1 Answer

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Final answer:

The function f(x) = (cosx)e²ˣ-1/e²ᵉ-ˣ-1+2 has no horizontal asymptote as x approaches positive infinity, but it has a horizontal asymptote at y = e as x approaches negative infinity.

Step-by-step explanation:

The function given is f(x) = (cosx)e²ˣ-1/e²ᵉ-ˣ-1+2. To find the horizontal asymptotes of the graph of f, we need to determine the behavior of f as x approaches positive infinity and negative infinity.

As x approaches positive infinity, the term e²ˣ in the numerator grows much faster than the other terms, so f(x) approaches infinity. Therefore, there is no horizontal asymptote as x approaches positive infinity.

As x approaches negative infinity, the term 1/e²ᵉ-ˣ-1 in the denominator approaches 0, while the other terms remain finite. Therefore, f(x) approaches a finite value. To find this value, we can take the limit of f(x) as x approaches negative infinity.

By applying L'Hopital's rule to the limit, we can find the value of the limit as x approaches negative infinity, which is e. Therefore, the graph of f has a horizontal asymptote at y = e as x approaches negative infinity.

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