Final answer:
The student seeks the time at which a block in SHM first reaches its rightmost position. Knowing that the period is 1.57 seconds, the answer is half of the period since the block starts from the leftmost point.
Step-by-step explanation:
The student is asking about the oscillation of a block attached to a spring and performing simple harmonic motion (SHM). Considering the block starts at a point 4.00 cm to the left of the equilibrium (which is -0.04 m) and is moving to the right, the time t1 at which it first reaches the furthest point on the right (its amplitude in the positive direction) can be found knowing the period of the motion. The block oscillates from x = -A to x = +A, where A is the amplitude.
From the information given, the period (T) of the oscillation is 1.57 seconds. To find the t1 when the block first reaches the limit of its motion to the right, we can use the fact that it takes half a period to go from one extreme to the other. Thus, t1 is T/2, which is 1.57 seconds / 2 or 0.785 seconds.