Final answer:
Anhydrous acetonitrile with less than 0.001 wt% water impurity equates to less than 10 ppm of water impurity.
Step-by-step explanation:
The question asks to convert the water impurity level from weight percent (wt%) to parts per million (ppm). Given that anhydrous acetonitrile contains less than 0.001 wt% water, we must express this amount as ppm. Since 1 wt% equals 10,000 ppm, we multiply 0.001 wt% by 10,000 to get the concentration in ppm:
0.001 wt% x 10,000 ppm/wt% = 10 ppm
Therefore, anhydrous acetonitrile with less than 0.001 wt% water impurity is equivalent to less than 10 ppm of water.