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Anhydrous acetonitrile contains less than 0.001 wt% water. Express the water impurity in ppm. A. 1000 ppm B. 10 ppm C. 0.000 01 ppm D. 100 ppm E 1 ppm ppm = parts per million = 1 106

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Final answer:

Anhydrous acetonitrile with less than 0.001 wt% water impurity equates to less than 10 ppm of water impurity.

Step-by-step explanation:

The question asks to convert the water impurity level from weight percent (wt%) to parts per million (ppm). Given that anhydrous acetonitrile contains less than 0.001 wt% water, we must express this amount as ppm. Since 1 wt% equals 10,000 ppm, we multiply 0.001 wt% by 10,000 to get the concentration in ppm:

0.001 wt% x 10,000 ppm/wt% = 10 ppm

Therefore, anhydrous acetonitrile with less than 0.001 wt% water impurity is equivalent to less than 10 ppm of water.

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