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The electric field strength 3.5 cm from the surface of a 10-cm -diameter metal ball is 70,000 n/c

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Final answer:

The charge on the metal ball is approximately 1.37 × 10^-18 C.

Step-by-step explanation:

The electric field strength of 70,000 N/C is given for a point located 3.5 cm from the surface of a 10-cm diameter metal ball. To calculate the charge on the metal ball, we can use the formula for electric force:



  1. F = q * E, where F is the electric force, q is the charge, and E is the electric field strength.
  2. We know the electric force is 9.60 × 10^-14 N and the electric field strength is 70,000 N/C, so we can rearrange the formula to solve for q: q = F/E.
  3. Substituting the given values, we get: q = (9.60 × 10^-14 N)/(70,000 N/C) = (9.60 × 10^-14 N)(1/70,000) = 1.37 × 10^-18 C.

Therefore, the charge on the metal ball is approximately 1.37 × 10^-18 C.

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