Question

According to the following reaction, how many moles of hydrogen peroxide (H2O2) are necessary to form 0.225 moles oxygen gas? Formula: hydrogen peroxide (H2O2) (aq) = water (l) + oxygen (g)

Answer 1

To produce 0.225 moles of oxygen gas (O2), you would need 0.45 moles of hydrogen peroxide (H2O2), based on the stoichiometric ratio from the balanced chemical equation.

Step-by-step explanation:

To determine how many moles of hydrogen peroxide (H₂O₂) are necessary to form 0.225 moles of oxygen gas (O₂), we look at the balanced chemical equation:

2 H₂O₂ (aq) → O₂ (g) + 2 H₂O (l).

This equation shows that 2 moles of H₂O₂ decompose to form 1 mole of O₂. Using this stoichiometric ratio, we can set up the following relationship:
(0.225 moles of O₂) × (2 moles of H₂O₂ / 1 mole of O₂) = 0.45 moles of H₂O₂

Therefore, 0.225 moles of oxygen gas will require 0.45 moles of hydrogen peroxide to be produced.