Final answer:
There are 0.1514 moles of Zn(NO₃)₂ in a 75.7 mL solution of 2.00 M Zn(NO₃)₂.
Step-by-step explanation:
To calculate the number of moles of Zn(NO₃)₂ in a solution, one employs the formula Moles = Molarity × Volume in liters. In this case, with a 75.7 mL solution and a molarity of 2.00 M, the volume is converted to liters by dividing 75.7 mL by 1000, yielding 0.0757 L.
Subsequently, the moles are determined by multiplying the molarity (2.00 M) by the volume in liters (0.0757 L), resulting in 0.1514 moles of Zn(NO₃)₂. This calculation is fundamental in quantitative chemistry, providing a means to ascertain the quantity of a substance within a given solution, essential for various applications such as chemical analysis and reaction stoichiometry.