Final answer:
The question requires solving for the maximum height and speed at impact of a projectile with an initial speed of 220 m/s at a 60° angle. Projectile motion equations, including kinematic formulas and Pythagorean theorem, are used to calculate these values.
Step-by-step explanation:
The student's question involves calculating the maximum height and speed at impact for a projectile fired at an initial speed of 220 m/s and an angle of 60°. These calculations are part of projectile motion, a topic in Physics.
To find the maximum height (H) reached by the projectile, we can use the formula H = (v^2 · sin^2(θ)) / (2 · g), where v is the initial speed, θ is the launch angle, and g is the acceleration due to gravity. Using the given initial speed (v = 220 m/s), angle (60°), and gravity (g = 9.8 m/s²), the calculation gives us the maximum height. The speed at impact (V) can be found using the kinematic equation that considers both horizontal and vertical components of velocity at impact. The horizontal component (Vx) remains constant, and the vertical component (Vy) at impact can be found using Vy = v · sin(θ) - g · t, where t is the total time of flight. The total impact speed is then obtained by the Pythagorean theorem, V = √(Vx^2 + Vy^2).