12.4k views
4 votes
draw the most stable form of the major product of the given molecule upon exposure to excess naoch3 in ch3oh , followed by aqueous acidic workup.

1 Answer

1 vote

Final answer:

The question involves the reaction of an unspecified molecule with NaOCH3 in CH3OH, suggesting an ester hydrolysis to form the most stable major product, typically a carboxylic acid and an alcohol.

Step-by-step explanation:

The question pertains to the reaction of a given molecule with NaOCH3 in CH3OH, followed by aqueous acidic workup to yield the most stable major product. The process described resembles the typical procedure for the hydrolysis of esters using methanolic NaOH, and subsequent neutralization. Although the precise molecule in question is not provided, this reaction generally leads to the formation of a carboxylic acid (or its salt, depending on the pH during workup) and an alcohol as the major product. The stability of the resulting product often depends on the minimization of steric hindrance and maximizing the delocalization of electrons.

The procedure provided suggests an ester hydrolysis under basic conditions, followed by neutralization with an acidic ion-exchange resin (amberlyte) to yield the free carboxylic acid. In the absence of specific structural information, it is indicated that the reaction proceeds with the typical selectivity and outcome associated with these conditions.

User Ben Botvinick
by
8.1k points