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Find the equation of the tangent plane to the surface at the given point z=ex-3y (3,1,1)?

User Woodii
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Final answer:

The equation of the tangent plane to the surface at the given point z=ex-3y (3,1,1) is z = 20.0855x - 3y - 39.0855.

Step-by-step explanation:

The equation of the tangent plane to the surface at the given point z=ex-3y (3,1,1) is:

First, we need to find the partial derivatives of z with respect to x and y.

∂z/∂x = e^x, ∂z/∂y = -3

Using the point (3,1,1), we can find the values of the partial derivatives: ∂z/∂x = e^3 = 20.0855, ∂z/∂y = -3

The equation of the tangent plane is given by: z - z0 = (∂z/∂x)(x-x0) + (∂z/∂y)(y-y0), where (x0,y0,z0) is the given point.

Substituting the values: z - 1 = 20.0855(x-3) - 3(y-1)

The equation of the tangent plane to the surface at the given point is: z = 20.0855x - 3y - 39.0855

User Christian Convey
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