Final answer:
Without the exact figures or context, we cannot provide a precise answer to the values of ft(-15, 30) and fv(-15, 30). In physics, these function values at a point typically relate to velocity and acceleration, which are found using the slopes of graphs in kinematics. Using provided kinematic equations, we can calculate acceleration given initial velocity, final velocity, and time interval.
Step-by-step explanation:
To estimate the values of ft(-15, 30) and fv(-15, 30), we must understand that these represent the function values at certain points and involve concepts of kinematics, specifically velocity and acceleration. In physics, to calculate the instantaneous velocity or acceleration at a point, we use the slope of the tangent to the position-time or velocity-time graph at that point.
For ft(-15, 30), if there is a figure accompanying this notation, it likely represents the position, and we would find the slope of the tangent at t = 30 seconds to find the velocity.
However, without specific data or the actual figures, we can't provide exact values. For fv(-15, 30), which seems to represent a velocity function at t = 30 seconds assuming the velocity is negative representing direction (such as west), the value appears to be about -0.24 m/s, but again, without the context, this is conjecture.
Using the given information related to average acceleration where the knowns are velocity vo = 30.0 km/h (converted to 8.333 m/s), final velocity vf = 0, and time interval At = 8.00s, we can calculate the acceleration. The change in velocity Δv would be vf - vo = -8.333 m/s since the vehicle is coming to a stop (vf = 0). Thus, the acceleration a would be calculated as Δv / At which results in -8.333 m/s2.
The complete question is: Estimate the values of ft(-15, 30) and fv(-15, 30). (Round your answers to two decimal places.)