Question

A certain 60.0 Hz AC power line radiates an electromagnetic wave having a maximum electric field strength of 30.5 kV/m. What is the wavelength of this very low-frequency electromagnetic wave?

Answer 1

The wavelength of the very low-frequency electromagnetic wave is approximately 5.00 x 10^6 meters.

Step-by-step explanation:

To find the wavelength of the electromagnetic wave, we can use the formula: wavelength = speed of light / frequency. In this case, the frequency is given as 60.0 Hz. The speed of light is approximately 3.00 x 10^8 meters per second.

Substituting these values into the formula, we get: wavelength = 3.00 x 10^8 m/s / 60.0 Hz = 5.00 x 10^6 meters.

Therefore, the wavelength of this very low-frequency electromagnetic wave is approximately 5.00 x 10^6 meters.