Final answer:
The compound formed between element X and sodium is Na₂X. Element X, which needs two electrons to achieve a noble gas configuration, would form an X²⁻ ion, and two Na+ ions from sodium would balance out the charges, making the statement true.
Step-by-step explanation:
The question is asking whether the compound formed between an element X with a ground state electron configuration of [Ne]3s²3p⁴ and sodium would be Na₂X. The element X has 6 valence electrons based on its electron configuration. Sodium, an alkali metal with an atomic number of 11, has a noble gas configuration of [Ne]3s¹, meaning it has one valence electron. When sodium forms an ionic compound, it tends to lose this single valence electron, forming a Na+ ion.
Element X is two electrons short of achieving a stable noble gas configuration, which suggests it would likely gain two electrons to complete its valence shell, forming an anion with a 2- charge (X²⁻). When sodium (Na+) and element X (X²⁻) combine to form an ionic compound, two sodium ions are needed to balance the two negative charges of X²⁻, resulting in the formula Na₂X. Therefore, the statement that the formula of the compound that X forms with sodium is Na₂X is true.