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A pair of fair dice is tossed. Find the probability of getting (a) a total of 3; (b) at most a total of 10.

(a) The probability of getting a total of 3 is 1/18
(b) The probability of getting at most a total of 10 is

User JonathanGB
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Final answer:

The probability of getting a total of 3 when rolling a pair of fair dice is 1/18. The probability of getting at most a total of 10 is 31/36.

Step-by-step explanation:

The probability of getting (a) a total of 3 when a pair of fair dice is tossed is 2/36, which simplifies to 1/18. To find this probability, we need to determine the number of favorable outcomes (rolls that result in a total of 3) and divide it by the total number of possible outcomes.

There is only one way to get a total of 3, which is by rolling a 1 on one die and a 2 on the other. Since each die has 6 sides, the total number of possible outcomes is 6*6 = 36. Therefore, the probability of getting a total of 3 is 1/18.

(b) To find the probability of getting at most a total of 10, we need to determine the number of favorable outcomes (rolls that result in a total of 10 or less) and divide it by the total number of possible outcomes.

To count the favorable outcomes, we can list all the possible combinations that result in a total of 10 or less:

  1. 1 + 1 = 2
  2. 1 + 2 = 3
  3. 1 + 3 = 4
  4. 1 + 4 = 5
  5. 2 + 1 = 3
  6. 2 + 2 = 4
  7. 2 + 3 = 5
  8. 3 + 1 = 4
  9. 3 + 2 = 5
  10. 4 + 1 = 5
  11. 6 + 4 = 10
  12. 5 + 1 = 6
  13. 4 + 2 = 6
  14. 5 + 2 = 7
  15. 6 + 3 = 9
  16. 3 + 3 = 6
  17. 4 + 3 = 7
  18. 5 + 3 = 8
  19. 6 + 2 = 8
  20. 6 + 1 = 7
  21. 4 + 4 = 8
  22. 5 + 4 = 9
  23. 6 + 5 = 11
  24. 5 + 5 = 10
  25. 4 + 5 = 9
  26. 3 + 4 = 7
  27. 2 + 5 = 7
  28. 3 + 5 = 8
  29. 2 + 6 = 8
  30. 1 + 5 = 6
  31. 1 + 6 = 7

Counting all the favorable outcomes, we can see that there are 31. Since the total number of possible outcomes is still 36, the probability of getting at most a total of 10 is 31/36.

User Savithru
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