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what will be the value of x after the following code is executed? int x = 10; for (int y = 5; y < 20; y +=5) x += y;

User Martinos
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1 Answer

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Final answer:

The value of x after the code is executed will be 60.

Step-by-step explanation:

The value of x after the code is executed can be determined by going through the loop:

  1. At the start, x = 10 and y = 5.
  2. x += y will add the value of y (5) to x (10), making x = 15.
  3. The loop continues and y is incremented by 5 each time until it reaches 20.
  4. This means that x += y will be executed four more times with y values of 10, 15, and 20.
  5. Therefore, the final value of x will be 10 + 5 + 10 + 15 + 20 = 60.

The value of x after the code is executed will be 60.

User DragonGamer
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