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Bookwork code: 6C

The table below shows information about the distances cycled by the members of a cycling club last week.
a) Work out an estimate for the mean distance cycled.
b) In which class does the median lie?
Distance cycled, d (km)
0 50 100 < d < 150
150 allowed
Frequency
4
10
2
9

1 Answer

5 votes

a) The mean distance cycled is estimated to be 94 km. b) The median lies in the class 100 km < d < 150 km.

a) Calculating the Mean

To estimate the mean distance cycled, we need to find the sum of all the distances and divide it by the total frequency. Using the given table:

0 km: Frequency = 4

50 km: Frequency = 10

100 km < d < 150 km: Frequency = 2

150 km: Frequency = 9

To find the sum, multiply each distance by its frequency and then add them up:

0 km * 4 = 0

50 km * 10 = 500

2 * [(100 + 150)/2] = 500

150 km * 9 = 1350

Sum = 0 + 500 + 500 + 1350 = 2350 km

To find the mean, divide the sum by the total frequency:

Mean = Sum / Total Frequency = 2350 km / (4 + 10 + 2 + 9) = 2350 km / 25 = 94 km

b) Locating the Median

To find the class in which the median lies, we need to arrange the distances in ascending order. The distances are: 0 km, 50 km, 100-150 km, 150 km.

The median is the middle value when the distances are arranged in order. Since the frequency of the 100-150 km class is 2, the median lies in this class. Therefore, the median lies in the class 100 km < d < 150 km.

The probable question may be:

How did you determine the class in which the median lies?

Why is the median located in the class 100 km < d < 150 km?

User JPGConnolly
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