Final answer:
The stretch in each spring for equilibrium of the 1.4-kg block is 0.343 m.
Step-by-step explanation:
To determine the stretch in each spring for equilibrium of the 1.4-kg block, we need to use Hooke's Law. Hooke's Law states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. The equation for Hooke's Law is F = kx, where F is the force exerted by the spring, k is the force constant, and x is the displacement of the spring.
Since the block is in equilibrium, the force exerted by the spring must be equal to the weight of the block. The weight of the block is given by the equation W = mg, where W is the weight, m is the mass of the block, and g is the acceleration due to gravity. Rearranging the equation, we have F = kx = mg.
To find the stretch in the spring, we can rearrange the equation to solve for x:
x = (mg)/(k)
Substituting the given values:
x = (1.4 kg)(9.8 m/s^2)/(40.0 N/m) = 0.343 m