Final answer:
To find the mass of water formed, use stoichiometry. For every 2 moles of H₂O₂, 2 moles of H₂O are formed. Convert the given mass of H₂O₂ to moles, then calculate the mass of H₂O using the mole ratio.
Step-by-step explanation:
To find the mass of water formed in the reaction, we need to use stoichiometry. The balanced equation for the reaction between hydrogen peroxide (H₂O₂) and water (H₂O) is:
2H₂O₂(aq) → 2H₂O(l) + O₂(g)
From the equation, we can see that for every 2 moles of H₂O₂, 2 moles of H₂O are formed. We can use this ratio to convert the given mass of hydrogen peroxide to moles, and then determine the mass of water formed:
First, calculate the moles of H₂O₂:
- 29.0 g H₂O₂ * (1 mol H₂O₂/34.02 g H₂O₂) = 0.853 mol H₂O₂
Next, use the mole ratio to find the moles of H₂O:
- 0.853 mol H₂O₂ * (2 mol H₂O/2 mol H₂O₂) = 0.853 mol H₂O
Finally, convert the moles of H₂O to grams:
- 0.853 mol H₂O * (18.02 g H₂O/1 mol H₂O) = 15.4 g H₂O
Therefore, 15.4 grams of water will be formed upon the complete reaction of 29.0 grams of hydrogen peroxide (H₂O₂).