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Find the volume V obtained by rotating the region bounded by the curves y = sin(x), y = 0, 0 ≤ x ≤ π/2 about the x-axis?

User Veljkoz
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1 Answer

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Final answer:

To find the volume obtained by rotating the region bounded by the curves y = sin(x), y = 0, 0 ≤ x ≤ π/2 about the x-axis, we can use the method of cylindrical shells.

Step-by-step explanation:

To find the volume obtained by rotating the region bounded by the curves y = sin(x), y = 0, 0 ≤ x ≤ π/2 about the x-axis, we need to use the method of cylindrical shells.

  1. First, let's set up the integral for the volume:
  2. V = ∫(0 to π/2) 2πx(f(x))dx, where f(x) is the top curve (y = sin(x)) and x is the variable of integration.
  3. Next, we express sin(x) in terms of y:
  4. x = arcsin(y)
  5. Substitute this into the integral:
  6. V = ∫(0 to 1) 2πarcsin(y)y dy
  7. Integrate using substitution or integration by parts to obtain the volume
User Marc LaFleur
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