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Assume that the four bases A, C, T, and G occur with equal likelihood in a DNA sequence of nine monomers. What is the probability of finding the sequence AAATCGAGT through random chance?

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Final answer:

The probability of finding the sequence AAATCGAGT through random chance can be calculated using the product rule of probability. The probability of each base occurring is 1/4.

Step-by-step explanation:

The probability of finding the sequence AAATCGAGT through random chance can be calculated using the product rule of probability. Since there are four bases (A, C, T, G) occurring with equal likelihood, the probability of each base occurring is 1/4.

Therefore, the probability of finding AAATCGAGT is (1/4) * (1/4) * (1/4) * (1/4) * (1/4) * (1/4) * (1/4) * (1/4) * (1/4) = 1/262,144, approximately.

This means that, through random chance, there is a 1 in 262,144 chance of finding the sequence AAATCGAGT in a DNA sequence of nine monomers, where the bases occur with equal likelihood.

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