Question

Calculate the displacement and velocity at times of (a) 0.500, (b) 1.00, (c) 1.50, and (d) 2.00 s for a ball thrown straight up with an initial velocity of 15.0 m/s. Take the point of release to be ________.

1) The ground
2) The top of a building
3) The height of the thrower
4) Cannot be determined

Answer 1

The displacement and velocity of a ball thrown straight up can be calculated using the equations of motion.

Step-by-step explanation:

To calculate the displacement and velocity of a ball thrown straight up with an initial velocity of 15.0 m/s at different times, we can use the equations of motion.

The equation for displacement is given by: Y = Yo + Vot - 1/2 * g * t^2, where Y is the displacement, Yo is the initial position (in this case, the point of release), Vo is the initial velocity, g is the acceleration due to gravity (approximately -9.8 m/s^2), and t is the time.

The equation for velocity is given by: V = Vo - g * t, where V is the velocity at a given time.

• At time 0.500 s, the displacement would be 5.85 m and the velocity would be 9.05 m/s.
• At time 1.00 s, the displacement would be 10.0 m and the velocity would be 4.90 m/s.
• At time 1.50 s, the displacement would be 11.6 m and the velocity would be -0.05 m/s.
• At time 2.00 s, the displacement would be 10.0 m and the velocity would be -4.90 m/s.