Final answer:
The electric fields at points A and B in the given scenario are 600 V/m and 350 V/m, respectively, calculated by the equation E = V/d. The electric potential isolines would be denser at point A than at point B, indicating a stronger electric field at A. Using these concepts, the electric field midway between A and B can be estimated at approximately 440 V/m.
Step-by-step explanation:
The question revolves around concepts of electric potential and electric field within the context of a physics course focused on electromagnetism. When dealing with electric potential and fields, it's important to remember key formulas and principles. For example, the electric field (E) is related to the electric potential (V) by the equation E = V/d, where d is the distance along the field line between two points of different potential.
In the scenario described, the potential difference between two points is given as 60 V. At point A, with an arc length of 10 cm (0.1 m), the electric field is calculated using the formula E = V/d, giving a value of 600 V/m. Similarly, at point B, where the arc length is 17 cm (0.17 m), the electric field would be 353 V/m (approximately 350 V/m as stated).
Regarding the density of electric potential isolines, we know that where these isolines are closer together, the electric field is stronger. Therefore, point A would have denser isolines compared to point B. Assuming a uniform field and linear decrease in potential, we can estimate that the electric field strength midway between points A and B (at an arc length of 13.5 cm or 0.135 m) would be around 444 V/m (rounded off to approximately 440 V/m as mentioned).