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Determine the latent heat of fusion of mercury using the following calorimeter data: 1.00 kg of solid hg at its melting point of -39.0 °c is placed in a 0.620- kg aluminum calorimeter with 0.400?

User Shuriquen
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Final answer:

The question seeks to determine the latent heat of fusion for mercury, but the calorimeter data provided is incomplete thus it cannot be calculated directly. For other substances with known latent heat of fusion, the calculation involves multiplying the mass by the latent heat of fusion.

Step-by-step explanation:

The question involves calculating the latent heat of fusion of mercury, which is a concept in thermodynamics within the field of Physics. To determine the latent heat of fusion, we would typically use calorimeter data involving the mass of the substance, the heat added or removed, and the temperature change. An equation commonly used is Q = mL, where Q is the heat transfer, m is the mass of the substance, and L is the latent heat of fusion. However, the provided calorimeter data for mercury is incomplete, so we cannot calculate the latent heat of fusion directly from the provided information.

As an example, if we consider another substance like aluminum, where we know the latent heat of fusion is 380 kJ/kg, we can calculate the heat required to melt a certain mass. If we have 7.00 kg of aluminum at its melting point, the amount of heat needed would be: Q = m * Lf = 7.00 kg * 380 kJ/kg = 2660 kJ.

User Avinash Solanki
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