Question

Calculate the work done by the gas during process 2→6. Express your answer in terms of p0 and v0.

Answer 1

The work done by the gas during a quasi-static and isothermal process from a state with pressure
`p_0` and volume
`v_0` to a state with volume
`4v_0` is
`p_0v_0ln(4)`.

The work done by the gas during process 2→6 can be calculated using the formula for work in thermodynamics, which is the product of the pressure and the change in volume.

The work done by a gas during an isothermal expansion of an ideal gas is given by the formula W = pV(ln(4)), where p is the initial pressure and V is the initial volume. Given that we are interested in expressing the answer in terms of
`p_0` and
`v_0`, we would substitute these values into our equation accordingly.

If the initial pressure is
`p_0` and the initial volume is
`v_0`, the work done by the gas would be
`p_0v_0ln(4)`.