Final answer:
The quadratic equation is solved using the quadratic formula to determine the maximum value of x. The positive value resulting from using the formula typically provides the maximum solution for x.
Step-by-step explanation:
The question involves solving a quadratic equation of the form ax² + bx + c = 0, which is a common problem in algebra. To find the maximum value for x1 and x2 in the given context, we would apply the quadratic formula x = (-b ± √(b² - 4ac)) / (2a). Here the 'a', 'b', and 'c' are coefficients from the quadratic equation. We can then evaluate the equation for both the positive and negative values in the numerator to find the potential solutions for x.
Given the equation x² + 0.0211x - 0.0211 = 0, plugging into the quadratic formula yields:
x = (-0.0211 ± √((0.0211)² - 4(1)(-0.0211))) / (2(1))
Calculating this will give us the two possible values for x. We typically take the greater value as the maximum, unless the context of the problem indicates otherwise.