Final answer:
The standard cell potential for the reaction 3Ni(s) + 2AI3+ (1M) -> 3NI2+ (1M) + 2AI(s) is -0.28 V.
Step-by-step explanation:
The standard cell potential, also known as the electromotive force (EMF), represents the maximum voltage generated by a electrochemical cell under standard conditions. To calculate the standard cell potential, we need to consider the reduction half-reactions of the species involved in the cell. For the given reaction 3Ni(s) + 2AI^(3+) (1M) -> 3NI^(2+) (1M) + 2AI(s), we can break it down into two half-reactions:
Ni(s) -> Ni^(2+) + 2e^-
AI^(3+) + 3e^- -> AI(s)
The standard electrode potentials for these half-reactions can be found in a table of standard electrode potentials. In this case, we are given that the potential for the oxidation of Ni to Ni^(2+) is 0.28 V. Remember that standard potentials are always given as reduction potentials, so we take the negative of the given value. Therefore, the standard cell potential for the given reaction is -0.28 V.