8.7k views
5 votes
A point charge of -3.00 μC is located in the center of a spherical cavity of radius 6.50 cm inside an insulating spherical charged solid. The charge density in the solid is 7.35 × 10⁻⁴ C/m³. What is the total charge enclosed by the spherical cavity?

1) 0 C
2) -3.00 μC
3) 3.00 μC
4) Cannot be determined

User Dmmfll
by
7.9k points

1 Answer

6 votes

Final answer:

To find the total charge enclosed by the spherical cavity, we need to calculate the charge inside the sphere. The charge density inside the solid is given as 7.35 × 10⁻⁴ C/m³.

Step-by-step explanation:

To find the total charge enclosed by the spherical cavity, we need to calculate the charge inside the sphere. The charge density inside the solid is given as 7.35 × 10⁻⁴ C/m³. The volume of the spherical cavity can be calculated as (4/3)πr³, where r is the radius of the cavity, which is 6.50 cm. The charge inside the cavity is then the product of the charge density and the volume of the cavity. This is equal to (7.35 × 10⁻⁴ C/m³) * ((4/3)π(6.50 cm)³). Converting the radius to meters, we have (7.35 × 10⁻⁴ C/m³) * ((4/3)π(0.065 m)³). Evaluating this expression will give us the total charge enclosed by the spherical cavity.

User Sunriser
by
8.1k points