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For which value of c is the matrix a = 3 2 -1 1 0 2 -2 -2 c not invertible?

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Final answer:

The value of c for which the matrix is non-invertible, or singular, is 0. The determinant of the matrix is zero when c is 0, indicating that it cannot be inverted.

Step-by-step explanation:

To determine the value of c which makes the matrix non-invertible, we need to find when the matrix has a determinant of zero. A matrix is non-invertible or singular if its determinant is zero. For the given matrix:

| 3 2 -1 |
| 1 0 2 |
|-2 -2 c |

the determinant is:

3(0*c - 2*(-2)) - 2(1*c - 2*(-2)) - 1(1*(-2) - 0*(-2))
= 3(2) - 2(c + 4) + 2
= 6 - 2c - 8 + 2
= 0 - 2c

Setting this equal to zero gives us the equation:

0 - 2c = 0

Solving this for c we find that c must be equal to 0.

Therefore, the value of c which makes this matrix non-invertible is 0.

User OammieR
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