Question

Excess electrons are placed on a small lead sphere with a mass of 8.05 g so that its net charge is -3.45×10⁻⁹ C. What is the charge-to-mass ratio of the sphere?

Answer 1

To calculate the charge-to-mass ratio of a lead sphere with a mass of 8.05 g and a net charge of -3.45×10⁻¹ C, we divide the total charge by the mass in kilograms, resulting in a charge-to-mass ratio of − 4.29 × 10⁻· C/kg.

Step-by-step explanation:

The question asks for the charge-to-mass ratio of a small lead sphere with a mass of 8.05 g and a net charge of -3.45×10⁻¹ C. To calculate the charge-to-mass ratio, we need to divide the charge by the mass. The ratio is calculated as follows:

Charge-to-mass ratio = Net charge / Mass of the sphere

Charge-to-mass ratio = (-3.45×10⁻¹ C) / (8.05 g)

Converting mass from grams to kilograms (since 1 kg = 1000 g):

Mass in kg = 8.05 g × (1 kg / 1000 g) = 8.05 × 10⁻³ kg

Charge-to-mass ratio = (-3.45×10⁻¹ C) / (8.05 × 10⁻³ kg)

Charge-to-mass ratio = − 4.29 × 10⁻· C/kg

Therefore, the charge-to-mass ratio of the lead sphere is − 4.29 × 10⁻· coulombs per kilogram (C/kg).