Final answer:
The ionization of CH3CH2CH2COOH in water results in the formation of acetate ion (CH3CH2CH2COO-) and hydronium ion (H3O+). The extent of ionization is generally less than 10%.
Step-by-step explanation:
The ionization of CH3CH2CH2COOH in water can be represented by the equation:
CH3CH2CH2COOH + H2O → CH3CH2CH2COO- + H3O+
When acetic acid (CH3COOH) dissolves in water, it ionizes into acetate ion (CH3COO-) and hydronium ion (H3O+). The equilibrium favors the reactants, so the extent of ionization of acetic acid in water is generally less than 10%.