Final answer:
To find the mass of CH4 gas that can be dissolved in water at 25°C and a CH4 partial pressure of 4.30 atm, we can use Henry's law. By using the equation C = k * P and converting units, we can calculate the concentration of CH4 gas in water and then find the mass of CH4 gas dissolved in water.
Step-by-step explanation:
To find the mass of CH4 gas that can be dissolved in water at 25°C and a CH4 partial pressure of 4.30 atm, we can use Henry's law. Henry's law states that the concentration of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. The equation for Henry's law is C = k * P, where C is the concentration of the gas, k is the Henry's law constant, and P is the partial pressure of the gas.
First, we need to convert the volume of water from mL to L. 575 mL is equal to 0.575 L. Next, we can use the equation C = k * P to calculate the concentration of CH4 gas in water. C = (1.4 × 10^-3 M/atm) * (4.30 atm) = 6.02 × 10^-3 M. Finally, we can calculate the mass of CH4 gas dissolved in water using the concentration and volume of water. Mass = concentration * volume = (6.02 × 10^-3 M) * (0.575 L) = 0.0034663 g. Therefore, the correct answer is B. 0.0035 g.