Final answer:
The current in the circuit would remain the same at 8 A, even if the battery voltage is increased by a factor of 3.
Step-by-step explanation:
First, let's use Ohm's law to find the resistance of the circuit. We know that the current is 8 A and the voltage is increased by a factor of 3, so the new voltage is 3 times the original voltage. Let's call the original voltage V and the new voltage V'. According to Ohm's law, V = IR, where I is the current and R is the resistance. So, we have V = 8A x R. When the voltage is increased by a factor of 3, we have V' = 24A x R. Since the current is the same, we can set V = V' and solve for R. 8A x R = 24A x R, which means that R is canceled out. This means that the resistance remains the same.
Therefore, the current in the circuit would remain the same at 8 A, even if the battery voltage is increased by a factor of 3.