The equation of the line passing through (0, 2) and (3, 0) is (2x + 3y = 6), as derived from the slope-intercept form. (option A)
To determine the equation of the line passing through the points (0, 2) and (3, 0), we can use the slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
First, calculate the slope (m):
![\[ m = \frac{{\text{{change in }} y}}{{\text{{change in }} x}} \]\[ m = \frac{{0 - 2}}{{3 - 0}} = \frac{{-2}}{{3}} \]](https://img.qammunity.org/2024/formulas/mathematics/college/migccmegnl5vv993eaw5vfamu4zwetdwkd.png)
Now, plug one of the points (let's use (0, 2)) and the calculated slope into the slope-intercept form to find the y-intercept (b):
![\[ 2 = \frac{{-2}}{{3}} \cdot 0 + b \]\[ b = 2 \]](https://img.qammunity.org/2024/formulas/mathematics/college/85yejzgdh66io8ppdx8432nxszv75ktjn2.png)
The equation of the line is then:
![\[ y = -\frac{{2}}{{3}}x + 2 \]](https://img.qammunity.org/2024/formulas/mathematics/college/z131ydoom1sv037rkhkzd5xjoc8es40npb.png)
Now, rearrange this equation to one of the given options:
![\[ 2x + 3y = 6 \]](https://img.qammunity.org/2024/formulas/mathematics/college/q344t3gat8dswjwbhnlef8gfj38c8r99ol.png)
So, the correct answer is:
![\[ \text{{A. }} 2x + 3y = 6 \]](https://img.qammunity.org/2024/formulas/mathematics/college/jy7jaiyulntd8auanbbdf6zn11cbuve2r7.png)