Final answer:
Without crossing over, an individual with the genotype AaBb at linked gene loci for genes A and B will produce gametes that are parental types, specifically AB and ab.
Step-by-step explanation:
The locus for gene A is linked to the locus for gene B. If meiosis occurs without any crossing over in an individual with linked genes, the types of gametes produced are parental types.
Considering the individual has the genotype AaBb, if the genes are linked and no crossing over takes place, the gametes expected would be either AB or ab, reflecting the original combinations of alleles present in the individual. Therefore, the correct answer is a. AB and ab.
In cases of genetic linkage, without crossing over, nonparental types such as Ab and aB, which would appear due to recombination, are not observed. Thus, in the absence of crossing over, the observed gametes preserve the combination of alleles that were together in the parent, also known as parental types.