Question

A baseball player throws a ball horizontally off a cliff that is 19.8 m tall. The ball lands 29.3 m away from the base of the cliff. What is the horizontal velocity of the ball?

Answer 1

v = 58.893 m/s

Step-by-step explanation:

I assume we are assuming -10 for gravity
Vertically:

Thrown vertically so initial vertical velocity is 0

Δy = vi*t + 0.5*a*t^2

-19.8 = 0*t + 0.5*-9.8*t^2

t^2 = 4.0408

t = 2.01s

Horizontally:

v = d*t

v = 29.3m * 2.01s

v = 58.893 m/s