Question

3. An over ripe papaya fruit falls from its tree and hit the ground below at 15 m/s, what should be the height from which the fruit falls?​

Answer 1

The height from which the overripe papaya fruit falls is 11.14 meters.

Step-by-step explanation:

In order to find the height from which the overripe papaya fruit falls, we can use the equation for free fall: h = 0.5 * g * t^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time. Since the fruit falls at a velocity of 15 m/s, we can use the equation v = g * t, where v is the velocity and t is the time. Rearranging the equation gives us t = v / g.

Substituting the given values into the equation, we have t = 15 m/s / 9.8 m/s^2 = 1.53 seconds.

Now we can substitute the value of time into the equation h = 0.5 * g * t^2 to find the height. h = 0.5 * 9.8 m/s^2 * (1.53 s)^2

= 11.14 meters.