The concentration of the NaOH is 0.250 M.
To calculate the concentration of NaOH, we can use the formula C1V1 = C2V2, where C1 is the concentration of the NaOH, V1 is the volume of the NaOH, C2 is the concentration of the HCl, and V2 is the volume of the HCl added to reach the equivalence point.
Given:
- V1 (volume of NaOH) = 50.0 mL
- V2 (volume of HCl) = 25.0 mL
- C2 (concentration of HCl) = 0.500 M
Using the formula, we can rearrange to solve for C1:
C1 = (C2 * V2) / V1
C1 = (0.500 M * 25.0 mL) / 50.0 mL
C1 = 0.250 M
Therefore, the concentration of the NaOH is 0.250 M.
The probable question may be:
A 50.0 mL sample of NaOH of unknown concentration is titrated with 0.500 M HCl. The equivalence point is determined to be when 25.0 mL of HCl are added to the NaOH. Show all calculations (with units and proper sig figs) for the questions below. No work shown = 0 points
Attach all work to this sheet.
1. Calculate the concentration of the NaOH. [NaOH]=_____ M
2. Calculate and record in the table the pH at each of the HCl volumes listed below.
3. Construct a titration curve of pH vs. volume of HCl added. Be sure to connect your data
points.
Volume of HCI Added (mL) | Calculated pH
0.0 |
5.0 |
10.0 |
15.0 |
20.0 |
24.0 |
25.0 |
26.0 |
30.0 |
35.0 |
40.0 |
45.0 |
50.0 |