Question

Construction workers are using a crane to lift a circular platform . The radius of the platform is 10 meters. A two-meter tall worker is directly under the center of the platform as it is lifted. When the platform is 24 meters above the ground, the cable snaps and the platform starts to fall It takes 0.75 seconds for the worker to notice the platform is falling. What is the minimum acceleration the workman must have to get out of the way of the platform ?

Answer 1

The minimum acceleration the workman must have to get out of the way of the falling platform is 64 m/s^2.

To calculate the minimum acceleration the worker must have to get out of the way of the falling platform, we need to consider the time it takes for the worker to react and move out of the way. In this case, the worker takes 0.75 seconds to notice the platform is falling. Using the equation for distance traveled during uniformly accelerated motion, we can calculate the minimum acceleration as:

a = 2d / t^2

where d is the distance traveled by the platform and t is the time taken to react. In this case, d is the height of the platform above the worker's initial position, which is 24 meters, and t is 0.75 seconds. Plugging in these values, we get:

a = 2(24) / (0.75^2) = 64 m/s^2

Therefore, the minimum acceleration the workman must have to get out of the way of the platform is 64 m/s^2.