Final answer:
To find the volume of neon gas at standard conditions, you use the combined gas law by converting the initial temperature to Kelvin and solving for the final volume using the standard condition values of pressure and temperature.
Step-by-step explanation:
The question involves the application of the ideal gas law to find the volume of neon gas at different conditions. To solve for the volume of a gas at standard conditions, which are 0°C and 1 atm, from given non-standard conditions (27°C and 985 torr), you can use the combined gas law:
V1 * P1 / T1 = V2 * P2 / T2
Here, V1 is the initial volume (105 mL), P1 is the initial pressure (985 torr), T1 is the initial temperature in Kelvin (K), which is 27°C + 273 = 300K, V2 is the final volume, P2 is the final pressure (760 torr, because 1 atm = 760 torr), and T2 is the final temperature in Kelvin, which is 0°C + 273 = 273K. Plugging in the values, we get:
V2 = (V1 * P1 * T2) / (P2 * T1)
V2 = (105 mL * 985 torr * 273K) / (760 torr * 300K)
V2 = (2843625) / (228000)
V2 = 124.72 mL
So, the neon gas would occupy a volume of 124.72 mL at standard conditions.