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The energy reased during this process is (mass of neutron =1.6725×10⁻²⁷ kg mass of proton =1.6725×10⁻²⁷ kg mass of electron =9×10⁻³¹ kg)

A. 0.506MeV
B. 7.10MeV
C. 6.39MeV
D. 5.4MeV

User Natbusa
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1 Answer

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The energy released during beta decay is approximately A. 0.506 MeV. Therefore , A. 0.506 MeV is correct.

The energy released during beta decay can be calculated using the mass-energy equivalence formula, E=mc², where E is the energy released, m is the mass difference between the parent and daughter nuclei, and c is the speed of light.

In beta decay, a neutron decays into a proton, an electron, and an antineutrino.

The mass difference between the neutron and the proton is:

Δm = (1.6725 × 10⁻²⁷ kg) - (1.6725 × 10⁻²⁷ kg) = 0

This means that no energy is released from the mass difference between the neutron and the proton.

However, there is a small mass difference between the electron and the antineutrino:

Δm = (9 × 10⁻³¹ kg) - (0 kg) = 9 × 10⁻³¹ kg

Plugging this value into the mass-energy equivalence formula, we get:

E = (9 × 10⁻³¹ kg) × (2.998 × 10⁸ m/s)²

E = 0.506 MeV

Therefore, the energy released during beta decay is approximately 0.506 MeV. The answer is A. 0.506MeV.

User SparkOn
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