Question

Swimming pools in club A and club B contain 500 and 200 liters of water, respectively. Water is pumped out of swimming pool A at a rate of q liters per minute and water is being added to swimming pool B at a rate of g liters per minute. How many hours will elapse before the two tanks contain equal amounts of water?

Answer 1

To find the time it will take for the two swimming pools to contain equal amounts of water, set up an equation using the rate at which water is being pumped out and added to each pool. Then, solve for the time when the two pools have equal amounts of water.

Step-by-step explanation:

To find the time it will take for the two swimming pools to contain equal amounts of water, we need to set up an equation.

Let's assume that after t minutes, the two swimming pools will contain equal amounts of water.

Therefore, the amount of water in pool A after t minutes can be given by: 500 - qt.

And the amount of water in pool B after t minutes can be given by: 200 + gt.

To find the time when the two pools have equal amounts of water, we can set the two equations equal to each other and solve for t:

500 - qt = 200 + gt

300 = (g + q)t

t = 300 / (g + q)

So, the two swimming pools will contain equal amounts of water after t = 300 / (g + q) minutes.