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A small, square loop carries a 43 A current. The on-axis magnetic field strength 42 cm from the loop is 7.0 nT

What is the edge length of the square?
Express your answer to two significant figures and include the appropriate units.

User Noam Peled
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1 Answer

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The edge length of the square is 5.2 meters.

The magnetic field of a square loop is given by:

B = (μ₀/2π) * (I * a)/(a² + d²)^(1/2)

where:

μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A)

I is the current (43 A)

a is the side length of the square loop (m)

d is the distance from the center of the loop (42 cm = 0.42 m)

We are given that B = 7.0 nT = 7.0 × 10⁻⁹ T. We can solve for a as follows:

a = (μ₀I / (2πB)) * √(a² + d²)

Substituting in the given values, we get:

a = (4π × 10⁻⁷ T·m/A * 43 A / (2π * 7.0 × 10⁻⁹ T)) * √(a² + (0.42 m)²)

Simplifying, we get:

a = 24.8 * √(a² + 0.1764 m²)

Squaring both sides, we get:

a² = 615.04 + 24.8a² + 0.043264

Combining like terms, we get:

22.8a² = 615.0864

Dividing both sides by 22.8, we get:

a² = 27.021

Taking the square root of both sides, we get:

a = 5.19 m

Rounding to two significant figures, we get:

a ≈ 5.2 m

Therefore, the edge length of the square is 5.2 meters.

User Escrava
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