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A small 570-gram ball on the end of a thin, light rod is rotated in a horizontal circle of radius 0.80 m. What is the centripetal force acting on the ball?

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Final answer:

The centripetal force acting on the ball is 0 Newtons.

Step-by-step explanation:

The centripetal force acting on the ball can be calculated using the formula:

F = m * a_c

Where F is the centripetal force, m is the mass of the ball, and a_c is the centripetal acceleration.

The centripetal acceleration can be calculated using the formula:

a_c = (v^2) / r

Where v is the velocity of the ball and r is the radius of the circle.

Plugging in the given values:

  • Mass (m) = 570 grams = 0.57 kg
  • Radius (r) = 0.80 m

Assuming the ball is rotating at a constant velocity, we can calculate the centripetal acceleration and then the centripetal force:

  • Velocity (v) = 0 m/s (since no velocity is given)

Using the formula for centripetal acceleration:

a_c = (0^2) / 0.80 = 0 m/s^2

Substituting this value into the formula for centripetal force:

F = 0.57 * 0 = 0 N

Therefore, the centripetal force acting on the ball is 0 Newtons.

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