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Ken has $950 in a savings account at the beginning of the summer. He wants to have at least $600 in the account at the end of the summer. He withdraws $35 a week for entertainment. Write an inequality for the number of weeks Ken can withdraw money, and solve the inequality.

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Final answer:

Ken can withdraw $35 for entertainment each week for up to 10 weeks to maintain at least $600 in his savings account, based on solving the inequality 950 - 35w >= 600.

Step-by-step explanation:

The question involves creating and solving an inequality based on Ken's savings and weekly withdrawals for entertainment. To find the maximum number of weeks Ken can withdraw $35 while ensuring his savings account does not fall below $600, we set up an inequality. Ken starts with $950, and after w weeks of withdrawing $35 per week, he must have at least $600 left. The inequality representing this situation is:

950 - 35w ≥ 600

To solve for w, subtract 950 from both sides of the inequality:

-35w ≥ -350

Next, divide both sides by -35, remembering that dividing by a negative number reverses the inequality sign:

w ≤ 10

Therefore, Ken can withdraw money for up to 10 weeks without his savings falling below $600.

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