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A small artery has a length of 1.10 x 10�����m and a radius of 2.50 x 10������m. If the pressure drop across the artery is 1.15kPa, what is the flow rate of blood through the artery?

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Final answer:

The flow rate of blood through the artery is approximately 2.790 x 10^-6 m^3/s.

Step-by-step explanation:

To find the flow rate of blood through the artery, we can use the Poiseuille's law formula:

Q = (Π * r^4 * ΔP) / (8 * η * l)

Where:

  • Q is the flow rate
  • r is the radius of the artery
  • ΔP is the pressure drop across the artery
  • η is the viscosity of the blood
  • l is the length of the artery

Plugging in the given values:

Q = (Π * (2.5 x 10-5)^4 * 1.3 x 103) / (8 * 1.14 x 10-3 * 1.1 x 10-3)

Simplifying the equation, we get:

Q ≈ 2.790 x 10-6 m3/s

Therefore, the flow rate of blood through the artery is approximately 2.790 x 10-6 m3/s.

User Gedean Dias
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