Final answer:
To burn 8 moles of hydrogen sulfide, you would need 12 moles of oxygen gas.
Step-by-step explanation:
In the balanced chemical equation:
2H₂S (g) + 3O₂ (g) → 2SO₂ (g) + 2H₂O(g)
we can see that 2 moles of hydrogen sulfide (H₂S) react with 3 moles of oxygen (O₂) to produce 2 moles of sulfur dioxide (SO₂) and 2 moles of water (H₂O).
Therefore, to burn 8 moles of hydrogen sulfide, we would need:
(8 moles H₂S) × (3 moles O₂ / 2 moles H₂S) = 12 moles O₂
So, 12 moles of oxygen gas would be needed to completely burn 8 moles of hydrogen sulfide.