Question

A ball is thrown straight up into the air at 18.2 m/s. How far does it travel after 1 s?

Answer 1

The ball thrown straight up into the air at 18.2 m/s travels a total of 13.3 meters after 1 second, taking into account the deceleration due to gravity.

Step-by-step explanation:

To calculate how far a ball travels after being thrown straight up into the air at 18.2 m/s for 1 second, we need to account for the acceleration due to gravity, which will slow the ball down as it travels upwards. The constant acceleration equation to use is:

`s = ut + (1)/(2)at^2`

where:

• s is the displacement (how far the ball will travel),
• u is the initial velocity (18.2 m/s),
• t is the time (1 s),
• a is the acceleration due to gravity (-9.8 m/s2, negative because it is in the opposite direction to the initial throw).

Using these values:

`s = 18.2 m/s * 1 s - (1)/(2) * 9.8 m/s2 * (1 s)2`

s = 18.2 m - 4.9 m

s = 13.3 m

So, the ball travels a total of 13.3 meters after 1 second.